By Ahmed Shamsul Arefin

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The prototype is char *strchr(char *str, int ch); The function strchr() searches str from left to right until the character ch is found or the terminating null character is found. If ch is found, a pointer to it is returned. If not, NULL is returned. When strchr() finds the character, it returns a pointer to that character. Knowing that str is a pointer to the first character in the string, you can obtain the position of the found character by subtracting str from the pointer value returned by strchr().

CHAPTER 3 PROGRAMMING IN C: A TUTORIAL 57 main() { char dest1[80]; char *dest2, *dest3; printf("\nsource: %s", source ); /* Copy to dest1 is okay because dest1 points to */ /* 80 bytes of allocated space. */ strcpy(dest1, source); printf("\ndest1: %s", dest1); /* To copy to dest2 you must allocate space. */ dest2 = (char *)malloc(strlen(source) +1); strcpy(dest2, source); printf("\ndest2: %s\n", dest2); return(0); } source: The source string. dest1: The source string. dest2: The source string.

Remember that by convention all character arrays are terminated with a `\0'. = '\0'; s++ ) n++; return(n); } You can now see why we have to say what kind of thing s points to -- if we're to increment it with s++ we have to increment it by the right amount. = '\0'; n++ ); The `*s' returns a character; the `++' increments the pointer so we'll get the next character next time around. As you can see, as we make things more efficient, we also make them less clear. But `*s++' is an idiom so common that you have to know it.

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